What is the compound interest on Rs 12600 for 2 years at 10% per annum compounded annually?

Solution : Here, Principal amount, `P = "Rs. 12,600` <br> Time, `t = 2` years<br> Rate `r = 10%` per annum<br> So, Amount, `A = P(1+r/100)^t`<br> `A = 12600(1+10/100)^2`<br> `A= 12600**11/10**11/10= "Rs. 15,246` <br> So, `C.I. = A-P = 15,246-12,600 = "Rs. 2,646`

Find compound interest on Rs 12600 for 2 years at 10% p.a. compounded annually.

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    What is the compound interest on Rs 12600 for 2 years at 10% per annum compounded annually?

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    What is the compound interest on Rs 12600 for 2 years at 10% per annum compounded annually?

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    Sum

    Find CI on Rs. 12600 for 2 years at 10% per annum compounded annually.

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    Solution

    We have,

    A = P`(1 + R/100)^n`, where Principal (P) = ₹ 12600, Rate (R) = 10, Number of years (n) = 2

    = ₹ 12600`(1 + 10/100)^2`

    = ₹ 12600`(11/10)^2`

    = ₹ `12600 xx 11/10 xx 11/10`

    = ₹ 15246.

    CI = A - P

    = ₹ 15246 - ₹ 12600 

    = ₹ 2646.

    Concept: Deducing a Formula for Compound Interest

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    Find the CI on Rs 12,600 for 2 years at 10% per annum compounded annually.

    Answer

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    Hint:This is a problem related to Compound Interest (CI). To find out the CI, principal amount, rate of interest and number of years for which the interest to be calculated have been given in the problem. Put these values in the standard formula to calculate CI. The standard formula to calculate final amount is as $A = P{(1 + \dfrac{R}{{100}})^n}$

    Complete step-by-step answer:
    Now, to calculate the compound interest, we should know the final amount after the given years, which can be expressed as
    $A = P{(1 + \dfrac{R}{{100}})^n}{\text{ }}...................{\text{ (1)}}$
    Where $A$ is the final amount, $P$ is the principal amount, $R$ is the rate of interest and $n$ is the number of years.
    In the question, it is given that
    $
      P = 12,600 \\
      R = 10\% {\text{ and}} \\
      n = 2{\text{ years}} $
    Now, putting these values in the equation (1) above, we will get the following expression,
    $
      A = 12600 \times {(1 + \dfrac{{10}}{{100}})^2} \\
      A = 12600 \times {(\dfrac{{11}}{{10}})^2} \\
      A = 12600 \times \dfrac{{121}}{{100}} \\
      A = 126 \times 121 \\
      A = 15246 $
    Now, we already know that $P$ is the principal amount 12,600
    Hence, interest compounded $CI$ in 2 years is as below,
    $
      CI = A - P \\
      CI = 15246 - 12600 \\
      CI = 2646 $
    Thus, the answer to the question, the Interest Compound $CI$ is Rs 2,646.

    Note:Interest to the principal amount is of two types.
    1.Simple Interest
    2.Compound Interest
    Both these interests are different in nature. The final amount with simple interest can be calculated in the following way,
    $A = P(1 + \dfrac{R}{{100}} \times n){\text{ }}.............{\text{ (2)}}$,
    Where $A$ is the final amount, $P$ is the principal amount, $R$ is the rate of interest and $n$is the number of years.
    You can easily understand from the two formulae, eq. (1) and (2), that the final amount calculated from these two formulae are very different and the amount calculated with formula (1) is higher as compared to the amount calculated with formula (2) when $n > 1$.

    What is the compound interest in ₹ on a sum of ₹ 12600 for 11 2 years at 20% per annum if the interest is compounded half yearly?

    ∴ The compound interest incurred is Rs. 4171.

    What is the compound interest on 10000 for 2 years at 10% per annum?

    Compound Interest would be 12100rs.

    What is the compound interest on rupees 20000 at 10% for 2 years?

    Where P is principal, R is rate of interest and T is time. ∴ The compound interest for 2 years is Rs. 2464.

    How do I calculate my CI for 2 years?

    Given:.
    Formula Used:.
    C.I = P[{1 + (R/100)}T - 1].
    Calculation:.
    C.I = 5000[{1 + (20/100)}2 - 1].
    ⇒ 5000[{1 + (1/5)}2 - 1].
    ⇒ 5000[(6/5)2 - 1].
    ∴ The compound interest is Rs. 2200..