What will be the interest on Rs 1200 principal for 2 years at the 10% simple interest rate?

Question

Use the formula for simple interest and then find the principal amount.

The correct answer is: 7400 Rupees

Complete step by step solution:Let the sum of money = PWe calculate simple interest by the formula,…(i)where P is Principal amount, T is number of years and R is rate of interestHere, we have T = 2,R = 10%, SI = 1480 and P = ?On substituting the known values in (i), we get Hence the sum of money P = 7400 Rupees.

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Related Questions to study

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Find the simple interest and amount on Rs 5000 in 3 years at 8% p.a.

Complete step by step solution:
We calculate simple interest by the formula,…(i)
where P is Principal amount, T is number of years and R is rate of interest
Here, we have T = 3,R = 8% and P = 5000
On substituting the known values in (i), we get

We have SI = 1200 Rupees.
We know the formula for total amount = A = P + SI…(ii)
where A is the total amount, P is the principal amount and SI is simple interest.
On substituting the known values in (ii), we get A = 5000 + 1200 = 6200
Hence total amount to be paid after 3 years = A = 6200 Rupees.

Find the simple interest and amount on Rs 5000 in 3 years at 8% p.a.

Maths-General

Complete step by step solution:
We calculate simple interest by the formula,…(i)
where P is Principal amount, T is number of years and R is rate of interest
Here, we have T = 3,R = 8% and P = 5000
On substituting the known values in (i), we get

We have SI = 1200 Rupees.
We know the formula for total amount = A = P + SI…(ii)
where A is the total amount, P is the principal amount and SI is simple interest.
On substituting the known values in (ii), we get A = 5000 + 1200 = 6200
Hence total amount to be paid after 3 years = A = 6200 Rupees.

Maths-

Find the amount to be paid at the end of 3 years, if principal is Rs 1800 at 9% p.a.

Complete step by step solution:
We calculate simple interest by the formula,…(i)
where P is Principal amount, T is number of years and R is rate of interest
Here, we have T = 3,R = 9% and P = 1800
On substituting the known values in (i), we get

We have SI = 486 Rupees.
We know the formula for total amount = A = P +SI…(ii)
where A is the total amount, P is the principal amount and SI is simple interest.
On substituting the known values in (ii), we get A = 1800 + 486 = 2286
Hence total amount to be paid after 3 years = A = 2286 Rupees.

Find the amount to be paid at the end of 3 years, if principal is Rs 1800 at 9% p.a.

Maths-General

Complete step by step solution:
We calculate simple interest by the formula,…(i)
where P is Principal amount, T is number of years and R is rate of interest
Here, we have T = 3,R = 9% and P = 1800
On substituting the known values in (i), we get

We have SI = 486 Rupees.
We know the formula for total amount = A = P +SI…(ii)
where A is the total amount, P is the principal amount and SI is simple interest.
On substituting the known values in (ii), we get A = 1800 + 486 = 2286
Hence total amount to be paid after 3 years = A = 2286 Rupees.

Maths-

Find the compound interest for 3 years on Rs 5000, if the rate of interest for the successive years are 8%, 6% and 10% respectively.

Complete step by step solution:
Given that principal amount P = 5000
Number of years T = 3
Let R1 = 8%,R2 = 6% and R3 = 10%

Total amount ,  …(i)
On substituting the known values in (i), we get

We know that, Compound interest ( CI) = total amount (A) - principal amount (P)
So, Compound interest ( CI) = 6296.4 - 5000 = 1296.4 Rupees

Find the compound interest for 3 years on Rs 5000, if the rate of interest for the successive years are 8%, 6% and 10% respectively.

Maths-General

Complete step by step solution:
Given that principal amount P = 5000
Number of years T = 3
Let R1 = 8%,R2 = 6% and R3 = 10%

Total amount ,  …(i)
On substituting the known values in (i), we get

We know that, Compound interest ( CI) = total amount (A) - principal amount (P)
So, Compound interest ( CI) = 6296.4 - 5000 = 1296.4 Rupees

Maths-

What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

Complete step by step solution:
Let the principal amount P = 1092
It is given that T = 2, R = 12%
We have the formula for annual payment …(i)
On substituting the known values in (i), we get

So, 325 Rupees is the annual instalment.

What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

Maths-General

Complete step by step solution:
Let the principal amount P = 1092
It is given that T = 2, R = 12%
We have the formula for annual payment …(i)
On substituting the known values in (i), we get

So, 325 Rupees is the annual instalment.

Maths-

What sum of money lent out at 6% for 2 years will produce the same interest as Rs. 1200 lent out at 5% for 3 years.

Complete step by step solution:
We calculate simple interest by the formula, …(i)
where P is Principal amount, T is number of years and R is rate of interest
Case Ⅰ
Let the sum of money = P
Here, we have 
On substituting the values in (i), we get …(ii)
Case Ⅱ
Here, we have 
On substituting the values in (i), we get …(iii)
It is given that the interest produced in both the cases is the same.
So, Equate (ii) and (iii)

On equating, we get 

 rupees.
Hence the sum of money P = 1500 Rupees

What sum of money lent out at 6% for 2 years will produce the same interest as Rs. 1200 lent out at 5% for 3 years.

Maths-General

Complete step by step solution:
We calculate simple interest by the formula, …(i)
where P is Principal amount, T is number of years and R is rate of interest
Case Ⅰ
Let the sum of money = P
Here, we have 
On substituting the values in (i), we get …(ii)
Case Ⅱ
Here, we have 
On substituting the values in (i), we get …(iii)
It is given that the interest produced in both the cases is the same.
So, Equate (ii) and (iii)

On equating, we get 

 rupees.
Hence the sum of money P = 1500 Rupees

Maths-

What sum of money lent out at 5% for 3 years will produce the same interest as Rs. 900 lent out at 4% for 5 years.

Complete step by step solution:
We calculate simple interest by the formula, …(i)
where P is Principal amount, T is number of years and R is rate of interest
Case Ⅰ
Let the sum of money = P
Here, we have 
On substituting the values in (i), we get …(ii)
Case Ⅱ
Here, we have 
On substituting the values in (i), we get …(iii)
It is given that the interest produced in both the cases is the same.
So, Equate (ii) and (iii)
On equating, we get

rupees.
Hence the sum of money P = 1200 Rupees

What sum of money lent out at 5% for 3 years will produce the same interest as Rs. 900 lent out at 4% for 5 years.

Maths-General

Complete step by step solution:
We calculate simple interest by the formula, …(i)
where P is Principal amount, T is number of years and R is rate of interest
Case Ⅰ
Let the sum of money = P
Here, we have 
On substituting the values in (i), we get …(ii)
Case Ⅱ
Here, we have 
On substituting the values in (i), we get …(iii)
It is given that the interest produced in both the cases is the same.
So, Equate (ii) and (iii)
On equating, we get

rupees.
Hence the sum of money P = 1200 Rupees

Maths-

Find the sum which will amount to Rs. 364.80 at 3 % per annum in 8 years at simple interest

Complete step by step solution:
Let the sum of money = P
We know the formula for total amount = A = P + SI
where A is the total amount, T is the principal amount and R is simple interest.
We know that 
where P is Principal amount, T is number of years and R is rate of interest
So, …(i)
Here, we have 
On substituting these values in (i), we get 
On further simplifications, we get

Hence the sum of money P = Rs 285.

Find the sum which will amount to Rs. 364.80 at 3 % per annum in 8 years at simple interest

Maths-General

Complete step by step solution:
Let the sum of money = P
We know the formula for total amount = A = P + SI
where A is the total amount, T is the principal amount and R is simple interest.
We know that 
where P is Principal amount, T is number of years and R is rate of interest
So, …(i)
Here, we have 
On substituting these values in (i), we get 
On further simplifications, we get

Hence the sum of money P = Rs 285.

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Complete step by step solution:
Let the sum of money = P
It is given that SI is  times the sum itself = P.
We calculate simple interest by the formula, 
where P is Principal amount, T is number of years and R is rate of interest
Here, we have 
On substituting the known values we get, 
On further simplifications, we have .

The simple interest on a sum of money at the end of 3 years is of the sum itself. What rate percent was charged?

Maths-General

Complete step by step solution:
Let the sum of money = P
It is given that SI is  times the sum itself = P.
We calculate simple interest by the formula, 
where P is Principal amount, T is number of years and R is rate of interest
Here, we have 
On substituting the known values we get, 
On further simplifications, we have .

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A theatre company uses the revenue function  dollars. The cost functions of the production . What ticket price is needed for the theatre to break even?

A theatre company uses the revenue function  dollars. The cost functions of the production . What ticket price is needed for the theatre to break even?

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Rewrite the equation as a system of equations, and then use a graph to solve.

Hint:
A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.
We are asked to rewrite the equation as system of equations and graph them to solve it.
Step 1 of 3:
Equate each side of the equation to a new variable, y:

Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.
 Note:
When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

Rewrite the equation as a system of equations, and then use a graph to solve.

Maths-General

Hint:
A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.
We are asked to rewrite the equation as system of equations and graph them to solve it.
Step 1 of 3:
Equate each side of the equation to a new variable, y:

Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.
 Note:
When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

Maths-

Rewrite the equation as a system of equations, and then use a graph to solve.

Thus, the solutions are (0, 0) and (1, -14)
Step 3 of 3:
Plot the points and join them to get the respective graph.

Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.
Note:
When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

Rewrite the equation as a system of equations, and then use a graph to solve.

Maths-General

Thus, the solutions are (0, 0) and (1, -14)
Step 3 of 3:
Plot the points and join them to get the respective graph.

Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.
Note:
When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

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Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

Complete step by step solution:
We calculate simple interest by the formula, 
where P is Principal amount, T is number of years and R is rate of interest
Here, we have 
On substituting the known values we get, 
On further simplifications, we have  rupees.
Thus, SI = 182 Rupees.

Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

Maths-General

Complete step by step solution:
We calculate simple interest by the formula, 
where P is Principal amount, T is number of years and R is rate of interest
Here, we have 
On substituting the known values we get, 
On further simplifications, we have  rupees.
Thus, SI = 182 Rupees.

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Rewrite the equation as a system of equations, and then use a graph to solve.

Here, they graphs intersect at two point; (-1 -1) and (0.5, 2). This means that the solutions of the system of equation are (-1 -1) and (0.5, 2).
Note:
Solutions of a set of equation can be found by graphing the equations and finding the intersecting points. The points where they intersect are the solutions.

Rewrite the equation as a system of equations, and then use a graph to solve.

Maths-General

Here, they graphs intersect at two point; (-1 -1) and (0.5, 2). This means that the solutions of the system of equation are (-1 -1) and (0.5, 2).
Note:
Solutions of a set of equation can be found by graphing the equations and finding the intersecting points. The points where they intersect are the solutions.

Maths-

Rewrite the equation as a system of equations, and then use a graph to solve.

The required points are: (-1, 4),(1, 4) and (0, 0)
Step 3 of 3:
Draw the graph of the set of equations, corresponding to the found points.

It is clear that there are no points of intersection. Hence, the given equation has no solution.
Note:
Maximum solutions possible for a quadratic equation are two. There are instances where the equation has no solutions as well.

Rewrite the equation as a system of equations, and then use a graph to solve.

Maths-General

The required points are: (-1, 4),(1, 4) and (0, 0)
Step 3 of 3:
Draw the graph of the set of equations, corresponding to the found points.

It is clear that there are no points of intersection. Hence, the given equation has no solution.
Note:
Maximum solutions possible for a quadratic equation are two. There are instances where the equation has no solutions as well.

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Find the simple interest on Rs. 8000 at 16 % per annum for 9 months?

Complete step by step solution:
We calculate simple interest by the formula,  
where P is Principal amount, T is number of years and R is rate of interest
Here, we have 
On substituting the known values we get, 
On further simplifications, we have  rupees.
Thus, SI = 1000 Rupees.

Find the simple interest on Rs. 8000 at 16 % per annum for 9 months?

Maths-General

Complete step by step solution:
We calculate simple interest by the formula,  
where P is Principal amount, T is number of years and R is rate of interest
Here, we have 
On substituting the known values we get, 
On further simplifications, we have  rupees.
Thus, SI = 1000 Rupees.

What will be the simple interest on Rs 1200 at 10 Pa for 2years?

What is the interest earned on Rs 1000 for 2 years at 10%?

What will be the compound interest of Rs 1200 at the rate of 5% for 2 years?

What will be the compound interest on a sum of Rs 1200 for 2 years at the rate of 20% per annum when the interest is compounded yearly?