When a subclass override a superclass method only the subclass version of the method can be called?

I was having an issue with a subclass's method getting called that overrode a method, so I created a small app to test it. When the superclass calls a method that its subclass overrides, the superclass's version of the method still gets called instead of the subclass's version, which overrides the superclass's method and should be the method getting called.

Expected output: sub foo

Actual output: super foo

Superclass:

class ViewController: UIViewController
{
    override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent)
    {
        foo()
    }

    func foo()
    {
        println("super foo")
    }
}

Subclass:

class SubclassViewController: ViewController
{
    override func foo()
    {
        println("sub foo")
    }
}

asked Aug 19, 2015 at 21:28

Adam EvansAdam Evans

2,05221 silver badges28 bronze badges

3

Make sure that the object's class is SubclassViewController. Otherwise, it will not have any knowledge of the method which is overriden by subclass

answered Aug 19, 2015 at 22:20

1

It's also worth checking that you're not trying to override in an extension. For some reason the override can't be done in an extension.

answered Mar 9, 2016 at 20:37

MikeCocoaMikeCocoa

3062 silver badges7 bronze badges

1

I just stumbled into this issue in Xcode 8.1 / Swift 3.0

I created a super class with a method stub with the intention of overriding it in my subclass, but calling it from the super and to my surprise the override wasn't being called.

My solution to the problem was to create a protocol. Using the OP's example, my solution looks like this:

Super:

class ViewController: UIViewController
{
    override func touchesBegan(touches: Set<NSObject>, withEvent event: UIEvent)
    {
        foo()
    }

}

Subclass:

class SubclassViewController: ViewController
{
    override func foo()
    {
        println("sub foo")
    }
}

Protocol:

protocol Fooizer {
   func foo() 
}

Protocol extension:

extension ViewController : Fooizer{
   func foo(){
      abort() //If you don't override foo in your subclass, it will abort
   }
}

answered Nov 12, 2016 at 1:22

0

In any object-oriented programming language, Overriding is a feature that allows a subclass or child class to provide a specific implementation of a method that is already provided by one of its super-classes or parent classes. When a method in a subclass has the same name, same parameters or signature, and same return type(or sub-type) as a method in its super-class, then the method in the subclass is said to override the method in the super-class.

Nội dung chính

• When a method is overridden in a subclass?
• What does it mean when a method is overridden?
• When a superclass method is overridden in a subclass The subclass version of may invoke the superclass version of a portion of the work?
• How a superclass method is overridden in a subclass?

Method overriding is one of the way by which java achieve Run Time Polymorphism.The version of a method that is executed will be determined by the object that is used to invoke it. If an object of a parent class is used to invoke the method, then the version in the parent class will be executed, but if an object of the subclass is used to invoke the method, then the version in the child class will be executed. In other words, it is the type of the object being referred to (not the type of the reference variable) that determines which version of an overridden method will be executed.

class Parent {

    void show()

    {

        System.out.println("Parent's show()");

    }

}

class Child extends Parent {

    @Override

    void show()

    {

        System.out.println("Child's show()");

    }

}

class Main {

    public static void main(String[] args)

    {

        Parent obj1 = new Parent();

        obj1.show();

        Parent obj2 = new Child();

        obj2.show();

    }

}

Output:

Parent's show() Child's show()

Rules for method overriding:

1. Overriding and Access-Modifiers : The access modifier for an overriding method can allow more, but not less, access than the overridden method. For example, a protected instance method in the super-class can be made public, but not private, in the subclass. Doing so, will generate compile-time error.

   class Parent {

       private void m1()

       {

           System.out.println("From parent m1()");

       }

       protected void m2()

       {

           System.out.println("From parent m2()");

       }

   }

   class Child extends Parent {

       private void m1()

       {

           System.out.println("From child m1()");

       }

       @Override

       public void m2()

       {

           System.out.println("From child m2()");

       }

   }

   class Main {

       public static void main(String[] args)

       {

           Parent obj1 = new Parent();

           obj1.m2();

           Parent obj2 = new Child();

           obj2.m2();

       }

   }

   Output:

   From parent m2() From child m2()
2. Final methods can not be overridden : If we don’t want a method to be overridden, we declare it as final. Please see Using final with Inheritance .

   class Parent {

       final void show() {}

   }

   class Child extends Parent {

       void show() {}

   }

   Output:

   13: error: show() in Child cannot override show() in Parent void show() { } ^ overridden method is final
3. Static methods can not be overridden(Method Overriding vs Method Hiding) : When you define a static method with same signature as a static method in base class, it is known as method hiding.

   The following table summarizes what happens when you define a method with the same signature as a method in a super-class.

   	Superclass Instance Method	Superclass Static Method
   Subclass Instance Method	Overrides	Generates a compile-time error
   Subclass Static Method	Generates a compile-time error	Hides

   class Parent {

       static void m1()

       {

           System.out.println("From parent "

                              + "static m1()");

       }

       void m2()

       {

           System.out.println("From parent "

                              + "non-static(instance) m2()");

       }

   }

   class Child extends Parent {

       static void m1()

       {

           System.out.println("From child static m1()");

       }

       @Override

       public void m2()

       {

           System.out.println("From child "

                              + "non-static(instance) m2()");

       }

   }

   class Main {

       public static void main(String[] args)

       {

           Parent obj1 = new Child();

           obj1.m1();

           obj1.m2();

       }

   }

   Output:

   From parent static m1() From child non-static(instance) m2()
4. Private methods can not be overridden : Private methods cannot be overridden as they are bonded during compile time. Therefore we can’t even override private methods in a subclass.(See this for details).
5. The overriding method must have same return type (or subtype) : From Java 5.0 onwards it is possible to have different return type for a overriding method in child class, but child’s return type should be sub-type of parent’s return type. This phenomena is known as covariant return type.
6. Invoking overridden method from sub-class : We can call parent class method in overriding method using super keyword.

   class Parent {

       void show()

       {

           System.out.println("Parent's show()");

       }

   }

   class Child extends Parent {

       @Override

       void show()

       {

           super.show();

           System.out.println("Child's show()");

       }

   }

   class Main {

       public static void main(String[] args)

       {

           Parent obj = new Child();

           obj.show();

       }

   }

   Output:

   Parent's show() Child's show()
7. Overriding and constructor : We can not override constructor as parent and child class can never have constructor with same name(Constructor name must always be same as Class name).
8. Overriding and Exception-Handling : Below are two rules to note when overriding methods related to exception-handling.
   • Rule#1 : If the super-class overridden method does not throw an exception, subclass overriding method can only throws the unchecked exception, throwing checked exception will lead to compile-time error.

     class Parent {

         void m1()

         {

             System.out.println("From parent m1()");

         }

         void m2()

         {

             System.out.println("From parent  m2()");

         }

     }

     class Child extends Parent {

         @Override

         void m1() throws ArithmeticException

         {

             System.out.println("From child m1()");

         }

         @Override

         void m2() throws Exception

         {

             System.out.println("From child m2");

         }

     }

     Output:

     error: m2() in Child cannot override m2() in Parent void m2() throws Exception{ System.out.println("From child m2");} ^ overridden method does not throw Exception
   • Rule#2 : If the super-class overridden method does throws an exception, subclass overriding method can only throw same, subclass exception. Throwing parent exception in Exception hierarchy will lead to compile time error.Also there is no issue if subclass overridden method is not throwing any exception.

     class Parent {

         void m1() throws RuntimeException

         {

             System.out.println("From parent m1()");

         }

     }

     class Child1 extends Parent {

         @Override

         void m1() throws RuntimeException

         {

             System.out.println("From child1 m1()");

         }

     }

     class Child2 extends Parent {

         @Override

         void m1() throws ArithmeticException

         {

             System.out.println("From child2 m1()");

         }

     }

     class Child3 extends Parent {

         @Override

         void m1()

         {

             System.out.println("From child3 m1()");

         }

     }

     class Child4 extends Parent {

         @Override

         void m1() throws Exception

         {

             System.out.println("From child4 m1()");

         }

     }

     Output:

     error: m1() in Child4 cannot override m1() in Parent void m1() throws Exception ^ overridden method does not throw Exception
9. Overriding and abstract method: Abstract methods in an interface or abstract class are meant to be overridden in derived concrete classes otherwise a compile-time error will be thrown.
10. Overriding and synchronized/strictfp method : The presence of synchronized/strictfp modifier with method have no effect on the rules of overriding, i.e. it’s possible that a synchronized/strictfp method can override a non synchronized/strictfp one and vice-versa.

Note :

1. In C++, we need virtual keyword to achieve overriding or Run Time Polymorphism. In Java, methods are virtual by default.
2. We can have multilevel method-overriding.

   class Parent {

       void show()

       {

           System.out.println("Parent's show()");

       }

   }

   class Child extends Parent {

       void show() { System.out.println("Child's show()"); }

   }

   class GrandChild extends Child {

       void show()

       {

           System.out.println("GrandChild's show()");

       }

   }

   class Main {

       public static void main(String[] args)

       {

           Parent obj1 = new GrandChild();

           obj1.show();

       }

   }

   Output:

   GrandChild's show()
3. Overriding vs Overloading :
   
   1. Overloading is about same method have different signatures. Overriding is about same method, same signature but different classes connected through inheritance.

   2. Overloading is an example of compiler-time polymorphism and overriding is an example of run time polymorphism.

Why Method Overriding ?

As stated earlier, overridden methods allow Java to support run-time polymorphism. Polymorphism is essential to object-oriented programming for one reason: it allows a general class to specify methods that will be common to all of its derivatives while allowing subclasses to define the specific implementation of some or all of those methods. Overridden methods are another way that Java implements the “one interface, multiple methods” aspect of polymorphism.

Dynamic Method Dispatch is one of the most powerful mechanisms that object-oriented design brings to bear on code reuse and robustness. The ability to exist code libraries to call methods on instances of new classes without recompiling while maintaining a clean abstract interface is a profoundly powerful tool.

Overridden methods allow us to call methods of any of the derived classes without even knowing the type of derived class object.

When to apply Method Overriding ?(with example)

Overriding and Inheritance : Part of the key to successfully applying polymorphism is understanding that the superclasses and subclasses form a hierarchy which moves from lesser to greater specialization. Used correctly, the superclass provides all elements that a subclass can use directly. It also defines those methods that the derived class must implement on its own. This allows the subclass the flexibility to define its methods, yet still enforces a consistent interface. Thus, by combining inheritance with overridden methods, a superclass can define the general form of the methods that will be used by all of its subclasses.

Let’s look at a more practical example that uses method overriding. Consider an employee management software for an organization, let the code has a simple base class Employee, the class has methods like raiseSalary(), transfer(), promote(), .. etc. Different types of employees like Manager, Engineer, ..etc may have their implementations of the methods present in base class Employee. In our complete software, we just need to pass a list of employees everywhere and call appropriate methods without even knowing the type of employee. For example, we can easily raise the salary of all employees by iterating through the list of employees. Every type of employee may have its logic in its class, we don’t need to worry because if raiseSalary() is present for a specific employee type, only that method would be called.

class Employee {

    public static int base = 10000;

    int salary()

    {

        return base;

    }

}

class Manager extends Employee {

    int salary()

    {

        return base + 20000;

    }

}

class Clerk extends Employee {

    int salary()

    {

        return base + 10000;

    }

}

class Main {

    static void printSalary(Employee e)

    {

        System.out.println(e.salary());

    }

    public static void main(String[] args)

    {

        Employee obj1 = new Manager();

        System.out.print("Manager's salary : ");

        printSalary(obj1);

        Employee obj2 = new Clerk();

        System.out.print("Clerk's salary : ");

        printSalary(obj2);

    }

}

Output:

Manager's salary : 30000 Clerk's salary : 20000

Related Article:

• Dynamic Method Dispatch or Runtime Polymorphism in Java
• Overriding equals() method of Object class
• Overriding toString() method of Object class
• Overloading in java
• Output of Java program | Set 18 (Overriding)

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When a method is overridden in a subclass?

The ability of a subclass to override a method allows a class to inherit from a superclass whose behavior is "close enough" and then to modify behavior as needed. The overriding method has the same name, number and type of parameters, and return type as the method that it overrides.

What does it mean when a method is overridden?

In Java, method overriding occurs when a subclass (child class) has the same method as the parent class. In other words, method overriding occurs when a subclass provides a particular implementation of a method declared by one of its parent classes.

When a superclass method is overridden in a subclass The subclass version of may invoke the superclass version of a portion of the work?

When a superclass method is overridden in a subclass, the subclass version often calls the superclass version to do a portion of the work. Failure to prefix the superclass method name with the keyword super and a dot (.)

How a superclass method is overridden in a subclass?

A subclass within the same package as the instance's superclass can override any superclass method that is not declared private or final. A subclass in a different package can only override the non-final methods declared public or protected.

When a subclass overrides a superclass method?

When a subclass method has the same name as a superclass method the subclass method overrides the superclass method?

How do you invoke an overridden superclass method from the subclass?

Can a subclass call a superclass method?