Consider a trihybrid cross with the allele pairs (W, w), (G, g), and (P, p), where W is a dominant allele for round seeds and w is a recessive allele for wrinkled seeds, G is a dominant allele for yellow seeds and g is a recessive allele for green seeds, and P is a dominant allele for purple flowers and p is a recessive allele for white flowers. Estimate the probability that an offspring genotype is Ww Gg Pp without using the Punnett square. Likewise, estimate the probability that an offspring phenotype is round, yellow, and purple. Show
With independent assortment, the genotype frequency for Ww Gg Pp can be estimated by multiplying the frequencies ½ × ½ × ½ = 1/8 that correspond to the highlighted terms in the expression: Likewise, with independent assortment, the probability that an offspring phenotype is round, yellow, and purple can be estimated by multiplying the frequencies ¾ × ¾ × ¾ = 24/64 that correspond to the highlighted terms in the expression: During metaphase I, the orientation of maternal and paternal homologues at the metaphase plate is random (see Figure 4.11, page 129). Therefore, although each cell produced by meiosis contains only one of each homologue, the number of possible combinations of maternal and paternal homologues is 2n, where n = the haploid number of chromosomes. Random assortment in humans produces 223 (8,388,608) different combinations of chromosomes. Furthermore, because of crossing over, none of these chromosomes is "purely" maternal or paternal. Thus, it is safe to conclude that of all the billions of sperm produced by a man during his lifetime (and the hundreds of eggs that mature over the life of a woman), it is unlikely that any two have exactly the same gene content. The random alignment of nonhomologous chromosomes at the metaphase plate results in the independent assortment of genes. Recommended textbook solutionsBiology1st EditionKenneth R. Miller, Levine 2,591 solutions Hole's Human Anatomy and Physiology13th EditionDavid N. Shier, Jackie L. Butler, Ricki Lewis 1,402 solutions
Human Resource Management15th EditionJohn David Jackson, Patricia Meglich, Robert Mathis, Sean Valentine 249 solutions Biology12th EditionSylvia Mader 1,423 solutions 26) Assuming independent assortment, an individual of genotype SsYyAa would produce gametes of genotypes (in their correct proportions) _____. a) 1/6 SYA, 1/6 SYa, 1/6 Sya, 1/6 sYa, 1/6 syA, and 1/6 sya Recommended textbook solutionsHuman Resource Management15th EditionJohn David Jackson, Patricia Meglich, Robert Mathis, Sean Valentine 249 solutions
Century 21 Accounting: General Journal11th EditionClaudia Bienias Gilbertson, Debra Gentene, Mark W Lehman 1,009 solutions Social Psychology10th EditionElliot Aronson, Robin M. Akert, Samuel R. Sommers, Timothy D. Wilson 525 solutions HDEV56th EditionSpencer A. Rathus 380 solutions What is the genotypic ratio of a monohybrid cross between two heterozygous parents?The expected genotype ratio when two heterozygotes are crossed is 1 (homozygous dominant) : 2 (heterozygous) : 1 (homozygous recessive).
What are the phenotypic ratios for a monohybrid cross when both parents are heterozygous?A monohybrid cross results in a phenotypic ratio of 3:1 (dominant to recessive), and a genotypic ratio of 1:2:1 (homozygous dominant to heterozygous to homozygous recessive).
What is the genotypic ratio of 2 heterozygous parents in a Dihybrid cross?Crossing of two heterozygous individuals will result in predictable ratios for both genotype and phenotype in the offspring. The expected phenotypic ratio of crossing heterozygous parents would be 9:3:3:1.
What will the genotypic ratio be of a monohybrid cross of two individuals who are heterozygous for a trait quizlet?In a monohybrid cross between two heterozygous parents,what would be the expected genotype and phenotype ratio? The Genotype would be 3/4 will have the dominant trait and 1/4 recessive. The Phenotype will be 3-1 Dominant.
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